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Aug 4, 2023 · I'm willing to print a size_t value using the %zu format specifier in my format string, however, I always get "zu" as an output, rather than the actual value in my size_t variable: size_t Aug 23, 2021 · Apparently %zu is handled as not supported, which might not be necessarily true (A quick check with MinGW64's GCC 8 1 0 on Windows 10 shows the warning, but works ) However, MinGW also comes with a set of alternative implementations To use them, prefix the function names with __mingw_ (e g __mingw_printf) Jan 24, 2010 · 53 Yes, there is It is %zu (as specified in ANSI C99) Note that size_t is unsigned, thus %ld is double wrong: wrong length modifier and wrong format conversion specifier In case you wonder, %zd is for ssize_t (which is signed) Is using %zu correct syntax in a printf format string as shown in some C code found on Wikipedia? Asked 15 years, 10 months ago Modified 6 months ago Viewed 3k timesInstead of 123, I got zu Other specifiers work correctly If size_t exists shouldn't zu also be available in printf? Is this something I should contact my library vendor about, or is a library implementation allowed to exclude it?Jul 29, 2022 · What is the difference between %zu and %lu in string formatting in C? %lu is used for unsigned long values and %zu is used for size_t values, but in practice, size_t is just an unsigned long Mar 25, 2013 · MS Visual Studio didn't support %zu printf specifier before VS2013 Starting from VS2015 (e g _MSC_VER >= 1900) %zu is available As an alternative, for previous versions of Visual Studio if you are printing small values (like number of elements from std containers) you can simply cast to an int and use %d:Dec 25, 2016 · %zu for size_t, with %z for length, and %u for unsigned Details can be found at 7 21 6 1 The fprintf function 6 The flag characters and their meanings are: z Specifies that a following d, i, o, u, x, or X conversion specifier applies to a size_t or the corresponding signed integer type argument; or that a following n conversion specifier applies to a pointer to a signed integer type Oct 3, 2015 · The C spec seems to allow printf("%zd\n", sz) depending on how it is read: 7 21 6 1 The fprintf function z Specifies that a following d, i, o, u, x, or X conversion specifier applies to a size_t or the corresponding signed integer type argument; or that a following n conversion specifier applies to a pointer to a signed integer type corresponding to size_t argument C11dr §7 21 6 1 7 Should Oct 19, 2016 · size_t is trickier, which is why %zu was added in C99 If you can't use that, then treat it just like k (long is the biggest type in C89, size_t is very unlikely to be larger) If you don't get the format specifiers correct for the type you are passing, then printf will do the equivalent of reading too much or too little memory out of the
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